Question

Let us show that cosec square22 degree cot square 68 degree = sin square 22 degree + sin square 68 degree + cot square 68 degree

Answer 1

Answer:

Sin^2 22+sin^2 68/cos^2 22+cos^2 68+sin^2 63+sin^2 27

sin^2 22+ cos^2 22/sin^2 68+cos^2 68+sin^2 63+sin^227

=1/1+1

=2

so in this question you have two know

sinA =cos (90-A)

cosA=sin (90-A)

sin^2 A+cos^2 A=1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

LHS= cosec²22°cot²68°

=sec²68°cot²68° [cosec²(90°-68°)=sec²68°]

= 1/cos²68°×cos²68°/sin²68°

= 1/sin²68°

= cosec²68°

RHS= sin²22°+sin²68°+cot²68°

= sin²22°+cos²22°+cot²68°

= 1+cot²22°

= cosec²68°

SO, RHS=LHS(PROVED)