Question

Let us show that, cosec²22° cot²68° = sin²22° + sin²68° + cot²68°
Please solve it
No spam​

Answer 1

Answer:

Solution :-

$\mapsto$ L.H.S = cosec²22.cot²68

=> cosec²22°. cot²(90° - 22°)

=> cosec²22° . tan²22°

=> $\dfrac{1}{sin^{²}22°}$ . $\dfrac{sin^{²}22°}{cos^{²}22°}$

=> $\dfrac{1}{cos^{²}22°}$

$\implies$ sec²22°

Now,

$\mapsto$ R.H.S = sin²22 °+sin²68° +cot²68°

=> sin²22 + sin²(90° - 22°)+cot²(90° - 22°)

=> sin²22°+cos²22°+tan²22°

=> 1+tan²22°

$\implies$ sec²22°

$\therefore$ L.H.S = R.H.S

$\leadsto\large{\boxed{\underline{\underline{\bf{PROVED}}}}}$

Answer 2

cosec²22° cot²68° = sin²22° + sin²68° + cot²68°

Please solve itcosec²22° cot²68° = sin²22° + sin²68° + cot²68°

Please solve it