Question

Let us show that if n is any positive odd integer, then x+y
is a factor of x^n + y^n​

Answer 1

Step-by-step explanation:

if f (x) = f (y) then (x-y) is a factor of f. The remainder when (x-a) is divided into f (x) is f (a). In the case of the polynomial given, putting x = -y, i. e (x+y) = 0, for n odd gives an identically zero result and so (x+y) is a factor of the expression