Question

Let us show that the points (7,9),(3,-7) and (-3,3) are the vertices of right angled triangle by calculation​

Answer 1

Answer:

Step-by-step explanation:

Let the points are A (7,9) ,B(3,-7) and C(-3,3)

AB²=(7-3)²+(9+7)²=4²+16²=16+256=272

BC²=(3+3)²+(-7-3)²=6²+(-10)²=36+100=136

CA²=(-3-7)²+(3-9)²=(-10)²+(-6)²=136

We observe that

AB²=272=136+136=BC²+CA²

Thus by Pythagoras theorem ΔABC is a right angled triangle

with C as a right angle

Also BC=CA

Thus it is a isosceles right triangle