Question

Let us think about a puzzle.

There are two electonic devices on the

table.The device A makes BEEP sound in

every 1 minute.

The device B makes BEEP sound in every 62

seconds.

Both of the devices beeped at 10 O’clock.

The times of beeping the first device is

written as a sequence below

10:01:00 , 10:02:00 , 10:03:00 , 10:04:00 · · ·

a) Write the sequence of the beeping time

of the second device

b) What is the nearest time at which

the devices beeped together after 10

O’clock

need honest answer
please urgent
if u answer this I will sure make u Brillinst​

Answer 1

Step-by-step explanation:

Four different electronic devices make a beep after every 30 minutes, 1 hour, 3/2 hours and 1 hour and 45 minutes respectively. All the devices beeped together at 12 noon. When will they beep together again?

Wardrobe refresh sale.

Hello ‘Jay Prakash Yadav’…..

I think you are not able to understand the concept used by the others to solve the ques…..

Lets take a small similar example..

There are 2 bells: Bell A & Bell B

Bell A rings after every 2 mins & Bell B rings after every 3 mins. If at 12 noon both bells ring together, then the time after which they will again ring together:

Let do manually:

Bell A : 2 mins + 2 mins + 2 mins = 6 mins

Bell B: 3 mins + 3 mins = 6 mins

=> After 6 mins they will ring again. This is what L.C.M do (For the defn. of L.C.M search Wikipedia)…..

So return to the original ques.

Device A: 30 mins

Device B: 60 mins

Device C: 90 mins

Device D: 105 mins

So L.C.M of above devices is 1260 mins = 21 hrs.

That means they will make a beep together again after 21 hrs to 12 Noon, that is 9:00 am (12 noon + (12 + 9) = 9 am ) of next day…

Hope it Helps…..

PLEASE FOLLOW ME.....