Question

let us write a rationalising factor of the denominator of 5/√3-2, which is not its conjugate surd.​

Answer 1

Rationalise the Denominator of the Following - 5 / √3 - 2

Step-by-step explanation:

Here, the Rationalising Factor is - (√3 + 2)

$\frac{5}{ \sqrt{3} - 2 } \times \frac{ \sqrt{3} + 2 }{ \sqrt{3} + 2 } = \frac{5( \sqrt{3} + 2)}{( \sqrt{3} - 2)( \sqrt{3} + 2 } \\ = > \frac{5 \sqrt{3} + 10}{( \sqrt{3 {}^{2}) } - {2}^{2} } \\ using \: the \: identity \: ( \sqrt{a} + {b} )( \sqrt{a} - {b} ) = a - {b}^{2} \\ = > \frac{5 \sqrt{3} + 10}{ 3 - 4} = > \frac{5 \sqrt{3} + 10 }{ - 1} or \: - 5 \sqrt{3} + 10$

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