Question

Let us write by calculating the amount on rs 80,000 for 2×1/2 yrs at the rate of 5% compound interset per annum.

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Amount=1,32,300\:rupees}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies Principal(p) = 80,000 \: rupees \\ \\ \implies Time(t) = 2 \frac{1}{2} \: years \\ \\ \implies Rate(r) = 5\% \\ \\ \underline \bold{To \: Find: } \\ \implies Amount = ?$

• According to given question :

$\bold{Using \: formula \: of \: Compound \: Interest : } \\ \implies A = p(1 + \frac{r}{100} ) ^{ t } \\ \\ \implies A = 80000 \times (1 + \frac{5}{100} )^{ \frac{5}{2} } \\ \\ \implies A = 80000 \times ( \frac{20 + 1}{20} )^{ \frac{5}{2} } \\ \\ \implies A= 80000 \times (\frac{21}{20} )^{ \frac{5}{2} } \\ \\ \implies A= 80000 \times (1.05)^{ \frac{5}{2} } \\ \\ \implies A = 80000 \times 1.65375 \\ \\ \implies A = 8 \times 16537.5 \\ \\ \bold{\implies A = 1,32,300 \:rupees}$

Answer 2

$\implies a = p(1 + \frac{r}{100} ) ^{ t } \\ \\ \implies a = 80000 \times (1 + \frac{5}{100} )^{ \frac{5}{2} } \\ \\ \implies a = 80000 \times ( \frac{20 + 1}{20} )^{ \frac{5}{2} } \\ \\ \implies a = 80000 \times (\frac{21}{20} )^{ \frac{5}{2} } \\ \\ \implies a = 80000 \times (1.05)^{ \frac{5}{2} } \\ \\ \implies a = 80000 \times 1.65375 \\ \\ \implies a = 8 \times 165375 \\ \\ \bold{\implies a = 132300 \:rupees}$