Question

Let us write by calculating the amount on Rs 80000 for 2½ years at the rate of 5% compound interest per annum.​

Answer 1

Answer:

The functions of the given are : 1) PLASMA MEMBRANE or CELL MEMBRANE : ¤ It separates content of cell from its surroundings... ¤ It regulate the entry of certain solids and ions into the cell.27-Mar-2018\orange{\bold{\underbrace{\overbrace{❥Answer᎓}}}}❥Answer᎓

Integrate the function

\huge\green\tt\frac{ \sqrt{tanx} }{sinxcosx}}

⇛\huge\tt\frac{ \sqrt{tanx} }{sinxcosx}sinxcosxtanx

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⇛\huge\tt \frac{ \sqrt{tanx} }{sinxcosx \times \frac{cosx}{cosx}}sinxcosx×cosxcosxtanx

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⇛\huge\tt \frac{ \sqrt{tanx} }{sinx \times \frac{ {cos}^{2} x}{cosx}}sinx×cosxcos2xtanx ㅤ ㅤ ㅤ

⇛ \huge\tt\frac{ \sqrt{tanx} }{ {cos}^{2} x \times \frac{sinx}{cosx} }cos2x×cosxsinxtanx

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⇛\huge\tt\frac{ \sqrt{tanx} }{ {cos}^{2}x \times tanx }cos2x×tanxtanx

⇛\huge\tt {tan}^{ \frac{1}{2} - 1 } \times \frac{1}{ {cos}^{2} x}tan21−1×cos2x1 ㅤ ㅤ ㅤ ㅤ ㅤ

⇛\huge\tt {(tan)}^{ - \frac{ 1}{2} } \times \frac{1}{ {cos}^{2}x } = {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x⇛(tan)(tan)−21×cos2x1=(tanx)−21×sec2x⇛(tan)

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⇛\huge\tt {(tan)}^{ - \frac{ 1}{2} } \times \frac{1}{ {cos}^{2}x } = ∫ {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x \times dx⇛(tan)(tan)−21×cos2x1=∫(tanx)−21×sec2x×dx⇛(tan)

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\bold\blue{☛\: Let tanx=t}☛Lettanx=t

\bold\blue{☛ \:Differentiating \: both \: sides \: w.r.t.x}☛Differentiatingbothsidesw.r.t.x

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⇛\huge\tt {sec}^{2} x = \frac{dt}{dx}sec2x=dxdt

⇛\huge\tt{dx \frac{dt}{ {sec}^{2}x }}dxsec2xdt

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⇛\huge\tt∴∫ {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x \times dx∴∫(tanx)−21×sec2x×dx

⇛\huge\tt ∫ {(t)}^{ - \frac{1}{2} } \times {sec}^{2} x \times \frac{dt}{ {sec}^{2}x }∫(t)−21×sec2x