Question

Let us write the value of the distance of the point (-4,y) from origin is 5 units
Pls answer fast

Answer 1

SOLUTION

GIVEN

The distance of the point (-4,y) from origin is 5 units

TO DETERMINE

The value of y

EVALUATION

Here the distance of the point (-4,y) from origin (0,0) i

$\sf{ = \sqrt{ {( - 4 - 0)}^{2} + {(y - 0)}^{2} } }$

$\sf{ = \sqrt{16 + {y}^{2} } }$

Now it is given that The distance of the point (-4,y) from origin is 5 units

$\therefore \: \: \sf{ \sqrt{16 + {y}^{2} } = 5 }$

Squaring both sides we get

$\sf{16 + {y}^{2} = {5}^{2} }$

$\sf{ \implies \: 16 + {y}^{2} = 25 }$

$\sf{ \implies \: {y}^{2} = 25 - 16 }$

$\sf{ \implies \: {y}^{2} = 9 }$

$\sf{ \implies \: y = \pm \: 3 }$

Hence the required value is

$\sf{y = \pm \: 3}$

And the required points are ( - 4, 3), ( - 4, - 3)

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