Question

Let \vec{u} ​u ​⃗ ​​ = (6,0,-2) and \vec{v} ​v ​⃗ ​​ = (0,8,0). What is \vec{u} ​u ​⃗ ​​ X \vec{v} ​v ​⃗ ​​ ?

Answer 1

It has given that $\vec{u}=6\hat{i}+0\hat{j}-2\hat{k}$ and $\vec{v}=0\hat{i}+8\hat{j}+0\hat{k}$

To find : The cross product of $\vec{u}$ and $\vec{v}$ i.e., $\vec{u}\times\vec{v}$

solution : $\vec{u}\times\vec{v}=(6\hat{i}+0\hat{j}-2\hat{k})\times(0\hat{i}+8\hat{j}+0\hat{k})$

= (6i - 2k) × (8j )

= 6i × 8j - 2k × 8j

= 48 k - 16(-i)

= 48 k + 16i

= 16i + 48k

Therefore the cross product of $\vec{u}$ and $\vec{v}$ is (16, 0, 48).

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