Let w be the angular velocity of earth's rotation
about its axis. An object weighed by a spring
balance gives the same reading at the equator as at
a height h above the poles (h «<R). The height his
(g is acceleration due to gravity at poles)
'(1)w2*r2/g
(2) 2w²R²/g
(3)w^2r^2/2g
(4)w2r2/4g
Answers
Answered by
2
Answer:
solve and get the answer
Explanation:
g' = g(1-2h/R) = g - w2r
Answered by
3
Answer:
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