Question

let write the area of thd rectangle region whole the length is (8x+3y) cm and breadth is (8x-3y) cm​

Answer 1

Answer:

Area of the Rectangular regions is $64x^2-9y^2$.

Step-by-step explanation:

Given,

       Length of the rectangle =$8x+3y$

       Breadth of the rectangle =$8x-3y$

We know that,

   Area of the rectangle = Length ×Breadth

So,

Area of the rectangle =$(8x+3y)(8x-3y)$

  According distributive law of multiplication,

$8x(8x-3y)+3y(8x-3y)\\ \\ 8x\cdot 8x+8x \cdot (-3y)+ 3y \cdot 8x +3y \cdot (-3y)\\ \\ 64x^2-24xy+24xy-9y^2$

Due to same term with opposite term 24xy is cancelled out.

   $64x^2-9y^2$