Question

Let x=2-5t+6${t}^{2}$

Step1:Velocity, v=dx/dt=d(2-5t+6${t}^{2}$)

Step2:Or v=-5+12t

For initial velocity, t=0

So u=-5m/s

Here how the value obtained from step1 to 2?
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Answer 1

Answer: by formula v=dx\dt

X=2-5t+6t

If dx\dt=v

DT=dx-v

DX*dt=v

V=-5+12t

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Step-by-step explanation: