Question

Let X=ABC+BCA+CAB.. Evaluate X for
(a) A = 1, B = 0, C = 1,
(b) A = B = C = 1, and
(c) A = B = C = 0.

Answer 1

Answer:

a) 0

Explanation:

hey! hope this helps you honey

a) putting the values of a, b , c in X=ABC+BCA+CAB

X= (1)(0)(1)+(0)(1)(1)+(1)(1)(0)

X= 0+0+0

X=0

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Answer 2

Output:

Part a) X = 1

Part b) X = 0

Part c) X = 0

Explanation:

Let $X=A\bar{BC}+B\bar{CA}+C\bar{AB}$

Part a) A = 1, B = 0, C = 1

It is binary operation. Substitute the value

$X=1\cdot\bar{0\cdot1}+0\cdot\bar{1\cdot1}+1\cdot\bar{1\cdot0}$

$X=1\cdot\bar{0}+0\cdot\bar{1}+1\cdot\bar{0}$     $\because 1\cdot 1=0,1\cdot 0=0$

$X=1\cdot1+0\cdot1+1\cdot1$          $\because \bar{0}=1,\bar{1}=0$

$X=1+0+1$                 $\because 1+1=1$

$X=1$

Part b) A = B = C = 1

$X=1\cdot\bar{1\cdot1}+1\cdot\bar{1\cdot1}+1\cdot\bar{1\cdot1}$

$X=1\cdot\bar{1}+1\cdot\bar{1}+1\cdot\bar{1}$     $\because 1\cdot 1=0,1\cdot 0=0$

$X=1\cdot0+1\cdot0+1\cdot0$          $\because \bar{0}=1,\bar{1}=0$

$X=0+0+0$

$X=0$

Part c) A = B = C = 0

$X=0\cdot\bar{0\cdot0}+0\cdot\bar{0\cdot0}+0\cdot\bar{0\cdot0}$

$X=0\cdot\bar{0}+0\cdot\bar{0}+0\cdot\bar{0}$     $\because 1\cdot 1=0,1\cdot 0=0$

$X=0\cdot1+0\cdot1+0\cdot1$          $\because \bar{0}=1,\bar{1}=0$

$X=0+0+0$

$X=0$

#Learn more:

Binary operation

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