Question

Let x__ and let
1 1 1 2 x x
P= 0 2 2 , Q= 0 4 0
0 0 3 x x 6
and R = PQP__
Then which of the following options is/are correct?
A. For x = 0, if R 1 1 then a + b = 5
a =6 a,
b b

B. For x = 1, there exists a unit vector ___+___ +____ for which R= __ 0
__ = 0
__ 0
C. det R = det 2 x x + 8 , for all x x__
0 4 0
x x 5
D. There exists a real number x such that PQ = QP

Answer 1

Answer:

no

Step-by-step explanation:

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