Let X ∼ B(n = 10, p = 0.2). Find:
(i) P (X = 1).
(ii) P (X ≥ 1).
(iii) P (X ≤ 8).
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Answer:
2 * (0.8)⁹
1 - (0.8)¹⁰
1 - 39 * (0.2)¹⁰
Step-by-step explanation:
n = 10
p = 0.2
q = 1 - 0.2 = 0.8
P (X = 1) = ¹⁰C₁ p¹ q⁹
= 10 * (0.2) * (0.8)⁹
= 2 * (0.8)⁹
P (X ≥ 1) = 1 - P(0) = 1 - ¹⁰C₀ p⁰ q¹⁰
= 1 - (0.8)¹⁰
P (X ≤ 8) = 1 - P(9) - P(10)
= 1 - ¹⁰C₉ p⁹ q¹ - ¹⁰C₁₀ p¹⁰ q⁰
= 1 - 10 (0.2)⁹(0.8) - (0.2)¹⁰
= 1 - (0.2)⁹ ( 8 - 0.2)
= 1 - (0.2)⁹ ( 7.8)
= 1 - 39 * (0.2)¹⁰
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