let x be 3,4,6,8 determine weather relation r = (x,f(x) belongs to x , f(x)=x squared plus 1 from x to n is a function or not
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Answered by
9
A relation becomes a function, when every element in x has an unique pair in y or f(x) and there are no any empty values in f(x)
So, if the x values are limited to the given four values, they have only unique mappings in f(x).
And if it extends to n, still it will behave as a function
And so this relation is a Function
So, if the x values are limited to the given four values, they have only unique mappings in f(x).
And if it extends to n, still it will behave as a function
And so this relation is a Function
Fleshaan:
will it satisfy the situation given ?
can you please show the relations you got for it.
Can u say the range of f(x) is it from x to n as u mentioned in your question?
if the range of f(x) has other values other than the values obtained from x^2+1 values, then it can't be a function
for example of the range i.e., y has values from 3 to n and contains all values between them, then it will not be a function... because by doing x^2+1 , you get only 10,17,65 etc.. for given x
So if the range is from x to n then it is not a function
Answered by
11
Answer:yes k is a function from X to N
Step-by-step explanation:
X= {3,4,6,8}
f(x)=x2+2
R=(x,f(x)}
f(x)=x2+1=3sq+1=10
Like that
R={(3,10),(4,17),(6,37),(8,65)}
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