let x be a random variable which is uniformly chosen from the set ofpositive odd numbers less than 100. the expectation, e[x] is
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50 is the answer...not sure
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Expected E(x) = 50
Step-by-step explanation:
odd numbers from 1 to 100
1 , 3 , 5 , 7 , 9..................................................., 97 , 99
total numbers = n
99 = 1 + (n-1)2
=> n-1 = 98/2
=> n = 50
E(1) = 1/50
E(3) = 1/50
E(5) = 1/50
E(97) = 1/50
E(99) = 1/50
Expected E(x) = (1/50) + 3*(1/50) + ........................................+ 97(1/50) + 99(1/50)
= (1/50)(1 + 3 + ...............97 + 99)
=(1/50)(50/2)(1 + 99)
= (1/2 )* 100
= 50
Expected E(x) = 50
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