Math, asked by anjareddy40713, 3 months ago

let x be real number such that [x^2] = x+1 then no of solutions​

Answers

Answered by luckysingh8210
1

Answer:

NO

solution will be there .

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Answered by 0xXIshuRajputXx0
0

Answer:

let the number be x

(-6)^-1 * x = ( 9 )^-1

= > 1 / 6 * x = 1 / 9

= > x = 1 / 3 x ( - 2 ) / 1

= > - 2 / 3 .

Step-by-step explanation:

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