Question

Let x be the area of triangle.Find the area of triangle whose each side is twice the side of given triangle.

Answer 1

Area of first triangle = √s(s-a)(s-b)(s-c) = x


The area of new triangle will becomes 4 times of it

= 4x

EXPLAINATION :
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if side is doubled then perimeter and semiperimeter also becomes double

So,S becomes double


all sides be a , b , c

new sides = 2a,2b,2c

Area = √s(s-a)(s-b)(s-c)

= √2s(2s-2a)(2s-2b)(2s-2c)

= √2s 2(s-a) 2(s-b) 2(s-c)

= √16s(s-a)(s-b)(s-c)

= 4√s(s-a)(s-b)(s-c)

= 4x


Hope it helps u : )

Answer 2

Answer:

The answer will be 4 x.

Hope it helps