Question

let x be the greatest number of 4 digits which when divided by 15 20 and 28 leaves in each case the remainder 2 the sum of digits of x is

Answer 1

Firstly, we do this 1520-2=1518,and 28-2 =26.
Now, do HCF of 1518and26.
Then we get 26.
26is the greatest no of the following.

Answer 2

Answer:

The sum of digits of x is 23.

Step-by-step explanation:

Consider the provided information.

Let us first find the greatest 4 digit number which is divisible by 15, 20 and 28. then we will add 2, so that when divided by 15, 20, 28 leaves remainder 2.

The LCM of 15, 20 and 28 is:

15 = 5×3

20 = 5×4

28 = 7×2×2

LCM = 2×2×3×5×7 = 420

The largest 4 digit number which is divisible by 420 is 9660. As 420×23=9660.

Now add 2.

9660+2=9662

Thus, the number is 9662.

We need to find the sum of digits of x.

Therefore, 9+6+6+2=23

Hence, the sum of digits of x is 23.