Math, asked by amoghatiwari87, 15 days ago

Let x be the greatest number of 4 digits, which when divided by 15, 20 and 28 leaves in each case the remainder 2. The sum of digits of x is (a) 19 (b) 21 (c) 23 (d) 25.

Answers

Answered by khushikumari15122006

2

Answer:

Greatest 4 digit number = 9999.The greatest 4 digit number is divisible by 420 = 9660.The remainder in each case = 2.

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