Math, asked by akankahasingh, 1 year ago

let x be the smallest number which when added to 2000 makes the resulting number divisible by 12,16,18 and 21 the sum of the digits of x is

Answers

Answered by gargee7
10

L.C.M. of 12,16,18,21 is 1008

then mutiply by 2 =1008×2=2016

sum of the number of 16 is 1+6=7

Answered by FelisFelis
3

The sum of the digit is 7.

Step-by-step explanation:

Consider the provided information.

First calculate the LCM of 12,16,18 and 21

12=2×2×3

16=2×2×2×2

18=2×3×3

21=3×7

The LCM of 12,16,18 and 21  is 2×2×2×2×3×3×7=1008.

Now multiply it by 2.

1008×2=2016

Hence, 16 must be added to 2000 so that the number is divisible by 12,16,18 and 21.

The sum of the digit is 1+6=7

#Learn more

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