Let x be the tens digit and y be the units digit.
The number is 10x + y.
The reversed number is 10y + x.
x + y = 8 - (1)
10x + y - (10y + x) = 18
10x + y - 10y - x = 18
9x - 9y = 18
(2)
x - y=2
(3)
x + y + x - y = 8 + 2
2x = 10
x = 5
2) = 9:
1) + (3)
ubstitute x = 5 into (1): 5+ y = 8
y = 8 - 5
= 3
the required number is 53.
bercises
oond
5. 8 kg
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Answer:
we Have See a y is an X side they are not A x valid
ubstitute x 8+y they are a longer no. to Ex. Y is to Great than X Not a tens Digit
10x + y- ( 10 y+ x )
< used a D.g.t.s
9x - 9y = 18 (9x - 9y = 18 x_y )
also Explain they ------ A Valid No.
53 ..
3.8 kg
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