Let ξ = {x: x ϵ N, x ≤ 12}, A = {x: x ≥ 7} & B = {x: 4 ‹ x ≤ 9}. Find A'∩B' and Find (A∪B) ' and Find B' and Find A'.
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ξ= { 1,2,3,4,5,6,7,8,9,10 } as x is a natural number less than or equal to 10.
A= { 4,5,6,7,8,9,10 } as x is a number greater than or equal to 4 and the universal set is already defined as ξ.
And, B= { 3,4,5,6 } as x is a natural number less than 7 and more than 2.
Intersection of two sets has the elements common in both the sets.
So, A∩B= { 4,5,6 }.
And (A∩B)
′
=ξ−(A∩B)= {1,2,3,7,8,9,10 }
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