Question

let x1,x2,........... be positive integers in AP, such that x1+x2+x3=12 and x4+x6=14. Then x5 is​

Answer 1

Step-by-step explanation:

Given, x1,x2,........... be positive integers in AP

x1 = 3

x2 = 4

x3 = 5

here, x1+x2+x3 = 12

x4 = 6

x5 = 7

x6 = 8

here, x4+x6=14

.•. x5 = 7