Let x1 x2 x3 and x4 be independent normal random variables with zero mean and unit variance.The probability that x4 is smallest among four is
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As X1, X2, X3, and X4 are independent normal random variables with zero mean and unit variance.
Then P(X1 is the smallest )
= P(X2 is the smallest )
= P(X3 is the smallest)
= P(X4 is the smallest)
= 1/4
= 0.25.
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