Question

Let y = 2*log2 then dy/dx =​

Answer 1

Answer:

Let y= 2^u where u = log v where v= 2x. Then by chain rule. dy/dx = (dy/du)(du/dv)(dv/dx). = (2^u log 2)(1/v)(2). = 2^logv log2 (1/2x)2.

Answer 2

Answer:

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