Let y=f(x) be the function for which f(1) =14 f(2) =12f(5)=6andf(8)= 21 then (7)
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Step-by-step explanation:
Let, f(x)=ax+b
Put x=1, f(1)=a(1)+b
Therefore, -1=a+b (eqn1)
Put x=2, f(2)=2a+b
Therefore, 14=2a+b (eqn2)
Solve eqn 1 &2 simultaneously,
a=15, b=-16
which implies, f(x)=15x-16
Now, f(15)=15(15)-16=225–16=209
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