Question

let y=rootx+rootx+root x then dy/dx is equal to

Answer 1

$y = \sqrt{x} + \sqrt{x} + \sqrt{x}$

$y = 3 \sqrt{x}$

$dy \div dx \: = \: d(3 \sqrt{x} ) \div dx$

$= 3 d( \sqrt{x} ) \div dx$

$= 3 \times (1 \div 2)(x {}^{(1 \div 2 - 1)} )$

$= 3 \div 2 \sqrt{x}$



Thanks

Answer 2

Answer:

x/2y-1

Step-by-step explanation:

y=root(x+y)      as y=rootx+rootx.......

y^2=x+y

y^2-y=x

dy/dx (2y-1)=1

dy/dx=1/2y-1