let y varies directly as x.if y=12 ,when x=4, then find the linear equation?
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y=kx
k=3
y-12=1/k(x-4)
yk-12k=x-4
y(3)-x=12(3)-4
3y-x=32
k=3
y-12=1/k(x-4)
yk-12k=x-4
y(3)-x=12(3)-4
3y-x=32
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