Question

Let y = x^2 + x, the minimum value of y is​

Answer 1

Answer:

$y = {x}^{2} + x \\ if \: \: \: \: x = 1 \\ y = {1}^{2} + 1 \\ y = 2$

Answer 2

Answer:

y=x^2+x

when x=1

y=1^2+1

y=1+1

y=2