Math, asked by gudalapadmajark, 11 hours ago

Let Y= x³ (x²-3x+2)/ (x-4)³(x+5)(x-3)(x²+2x+2).

The complete set of value of x satisfying Y <0 belongs to the interval

(A) x € (-5, 0) (1, 2) (3, 4)

(C) x € (-1,0) U (1, 2) (4, 00)

(B) x € (-00, 0) (2, 3) (3, 4)

(D) x = [-1,0) [1, 2) U (3,00)​

Answers

Answered by tejrambhatt54
0

Answer:

Given,

(x−5)

5

(2x−7)

6

x

2

(3x−4)

3

(x−2)

4

≤0

2x−7

3x−4

≤0 and x=0,2,

=7/2

3

4

≤x<5 and x=0,2,

=7/2

Hence, number of integral solution is {0,2,3,4}=4

And number of positive integral solution are 2,3,4

Thus the number of integral solutions are 3

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