Math, asked by priyanegi9262001, 8 months ago

let z be a complex number such that the imaginary part of z is non zero and a= z^2 +z+1 is real. Then a cannot be value​

Answers

Answered by saliankrithika1
3

Answer:

The given equation is z

2

+z+1−a=0

If the solution is not real then Δ=b

2

−4ac of the quadratic ax

2

+bx+c=0 is less than zero.

⇒1−4(1−a)<0

⇒1−4+4a<0

⇒4a<3

⇒a<

4

3

Hence, all values of a less than

4

3

will give non-real solutions.

Options A, B and C are less than

4

3

.

Hence option D is correct

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