let z be a complex number such that |z-i/z-2i| = 1 and |z| = 5/2.
then the value of |z+3i| :
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Answer:
Given
∣
∣
∣
∣
∣
z+2i
z−i
∣
∣
∣
∣
∣
=1
⇒∣z−i∣=∣z+2i∣
Let z=x+iy
So, x
2
+(y−1)
2
=x
2
+(y+2)
2
−2y+1=4y+4
6y=−3⇒y=
2
−1
x
2
+y
2
=
4
25
⇒x
2
=
4
24
=6
z=±
6
−
2
i
∣z+3i∣=
6+
4
25
=
4
49
=
2
7
∴
∣2+3i∣=
2
7
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