Let Z1 and Z2 be the complex roots of ax^2+bx+c=0 where a≥b≥c>0. Then
a)|z1+z2|≤1
b)|z1+z2|>2
c)|z1|=|z2|=1
d) none
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If Z1 and Z2 are the complex roots of ax^2+bx+c=0 where a≥b≥c>0. Then
|z1+z2|>2 (option b).
Given that, we have a quadratic equation
ax^2+bx+c=0 where a≥b≥c>0
the equation has complex roots Z1 and Z2
We know that in a quadratic equation if one root is a complex number then the other root is the conjugate of the first root.
therefore,
if Z1 = x + iy
then Z2 = x - iy
Now
| Z1 + Z2 | = | x + iy + x - iy|
= | 2x |
We know that x is a real number therefore 2x will be greater than 0
2x > 2
Therefore, |z1+z2| = 2x > 2
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