Question

leter
I which of the following in the value of k, one
root of the quadratic equation.x2+kx-8=0is -4​

Answer 1

Answer:

Given kne root of the Q.E is -4 then,

(-4)²+k(-4)-8 = 0

16-4k-8 = 0

4k = 8

k = 2

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Answer 2

Step-by-step explanation:

let the other root be x

x^2-(sum of roots)x+product of roots=0

x^2-(-k)x-8=0

in comparing

-4*x=-8

x=2

-k=-4+2=-2

k=2

x^2+2x-8=0

x^2+4x-2x-8=0

x(x+4)-2(x+4)=0

(x+4)(x-2)=0

x=-4,2