Letf(x) = ax + bandg(x) = ex + d, where a, b, e,and d are constants. Detennine for which constants a, b, e, and d it is true that fog = go f.
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Step-by-step explanation:fog=f{g(x)}
=a(ex+d)+b
=aex+ad+b
gof=g{f(x)}
=e(ax+b)+d
=aex+eb+d
Therefore fog not equal to gof
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