Question

LETI
Section
Section II
Question 2 :
A car starts from rest and acquires a velocity of 54 km/h in 2s.
Find:
(a) its acceleration
(b) distance travelled by the car assuming its motion is uniform
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Answer 1

Explanation:

Given that,

Intial velocity u=0m/s

Final velocity v=54km/h=54×

18

5

=15m/s

Time t=2min=120s

Now, put the value in equation of motion

The acceleration is

v=u+at

a=

t

v−u

a=

120

15−0

a=o.125m/s

2

Now, again from equation of motion

The distance is

s=ut+

2

1

at

2

s=0+

2

1

×0.125×120×120

s=900m

Hence, the acceleration is 0.125m/s

2

and distance is 900m

Answer 2

Answer:

refer to the image please