Lets denotes the semi-perimeter of a
triangle ABC in which BC = a: CA = b and
AB = c. If a circle touches the sides
BC, CA, AB at D, E, F, respectively. Prove
that BD = S - b.
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2
Answer:
The figure is as shown in the attached image.
sinB=AB10=BC12
⇒BC=1.2AB=1.2AC
sin2A=ABBD=AB2BC=AB0.6AB=0.6
⇒cos2A=0.8andtan2A=0.80.6=43
⇒ADBD=43⇒BD=10×43=7.5
BC=2×BD=15
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