Math, asked by romitrandad, 5 months ago

Lets denotes the semi-perimeter of a
triangle ABC in which BC = a: CA = b and
AB = c. If a circle touches the sides
BC, CA, AB at D, E, F, respectively. Prove
that BD = S - b.

Answers

Answered by pradhanca132
2

Answer:

The figure is as shown in the attached image.

sinB=AB10=BC12

⇒BC=1.2AB=1.2AC

sin2A=ABBD=AB2BC=AB0.6AB=0.6

⇒cos2A=0.8andtan2A=0.80.6=43

⇒ADBD=43⇒BD=10×43=7.5

BC=2×BD=15

Answered by shikhu76
4

Answer:

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