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because angle. BAC =DAC.
&angle. DCA=BCA
&here. AC is common line b/w them
so
by (ASA) rule
∆BAC=~DAC
&angle. DCA=BCA
&here. AC is common line b/w them
so
by (ASA) rule
∆BAC=~DAC
Answered by
3
5. a) in triangleBAC and triangleDAC
angleBAC=angleDAC
AC=AC
angleBCA=angleDCA
triangleBAC=TriangleDAC by ASA congruence
b)AB=AD by cpct(or side opposite to equal angles)
c)CD=CB by cpct(or side opposite to equal angles)
6. a)in triangle ABD and triangle ADC
AB=AC
BD=CD(D is mid point of BC)
AD=AD
triangle ABD= triangle ADC by SSS
b)angle B = angle C by cpct
hope it helps u if yeah plz mark it brainliest
angleBAC=angleDAC
AC=AC
angleBCA=angleDCA
triangleBAC=TriangleDAC by ASA congruence
b)AB=AD by cpct(or side opposite to equal angles)
c)CD=CB by cpct(or side opposite to equal angles)
6. a)in triangle ABD and triangle ADC
AB=AC
BD=CD(D is mid point of BC)
AD=AD
triangle ABD= triangle ADC by SSS
b)angle B = angle C by cpct
hope it helps u if yeah plz mark it brainliest
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