Question

lets see who can solve this

Answer 1

Hello it's an easy question.Here is the solution:-
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Angle PQB=Angle QBC ( alternate interior angle) ---------(1)
Angle QBC=Angle RCD ( corresponding angles) --------(2)
From (1) & (2),
Angle PQB= Angle RCD
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RSDC is a parellelogram (as RS ll CD and RC ll SD )
, therefore RS =CD
Thus, PQ=CD (as PQ=RS)
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In triangles PQE and FCD
Angle QPE = Angle FDC ( alternate interior angle)
PQ=CD
Angle PQB =Angle RCD
By ASA congruence rule, Triangles PQE and FCD are congruent.
I.e. PQE= FCD. 'Proved'
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