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10.jiya walks 6 km east
and then 8 km north
now just draw the figure of this question.The figure is given in attachment.
We need to find the length of AC
By the Pythagoras theorem
H^2=P^2 +B^2
•AC^2= AB^2+BC^2
AC^2= 6^2+8^2
AC^2= 36+64
AC=√100
AC=10
Therefore,jiya is 10 Km far from her home position .
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