LETS SEE WHO HAS THE DARE TO SOLVE THIS
CLASS 10 CHAPTER PROBABILITY
(well I know/solved the ans I am asking just for fun)
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36+ R1+ R2+ R3= 50
R1+ R2+ R3= 14
R2+ R3=14-R1
R2: R3 = 4x:3x
4x+3x = 14-R1
7x = 14- R1
X = 14/7- R1/7
X= 2 -R1÷7
so
R2: R3 = 4(2 -R1÷7):3(2 -R1÷7)
8- 4R1/7 :6-3R1/7
I know just till now sorry as i am in 9 std only
If you know ans plz let me know and again sorry
R1+ R2+ R3= 14
R2+ R3=14-R1
R2: R3 = 4x:3x
4x+3x = 14-R1
7x = 14- R1
X = 14/7- R1/7
X= 2 -R1÷7
so
R2: R3 = 4(2 -R1÷7):3(2 -R1÷7)
8- 4R1/7 :6-3R1/7
I know just till now sorry as i am in 9 std only
If you know ans plz let me know and again sorry
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0
oh god bro it's tough in tenth class aaaa
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