Question

Letter F is formed from three identical rods of length l. Find coordinates of its
centre of mass.​

Answer 1

Answer:ye Allen Wala hai Kya

Explanation:

Answer 2

Answer:

The co ordinates of centre of mass of F is (1/3,1/6)

Explanation:

Given:

An F shaped figure made with three identical rods

Each of length L

We know that,

The Centre of mass of each rod lies at the centre.

S according to the figure,

Centre of mass of 1st rod will be at (0,0)

Centre of mass of 2nd-rod will be at (1/2,0)

Centre of mass of 3rd-rod will be at (1/2,1/2)

Let the mass of each rod be m (since they are identical)

Now,

The Centre of mass of the whole system (in x)

$x = \frac{mx_{1} +mx_{2} + mx_{3}}{m_{1} + m_{2} + m_{3}}$

$x = \frac{mx_{0} +mx_{1/2} + mx_{1/2}}{m + m+ m}$         since  $m_{1} = m_{2} = m_{3}$

$x = \frac{m_{l} }{3m} \\\\x = l/3$

The Centre of mass of the whole system (in y)

$y = \frac{my_{1} +my_{2} + my_{3}}{m_{1} + m_{2} + m_{3}}$

$x = \frac{my_{0} +my_{0} + my_{1/2}}{m + m+ m}$

$y = \frac{m_{l}}{3m*2}\\y = 1/6$

Hence, the co ordinates of centre of mass of F is (1/3,1/6)