Question

lettered angle calculate the size ​

Answer 1

Answer:

In ΔABC,

AC = BC (Given)

∠ABC=∠BAC (∠s opposite to equal sides)

∠ABC=32

∘

⇒x=32°

Now, y=32°+32°=64°

(∴ Exterior angle = Sum of two opposite interior ∠s)

In ΔBCD,

BC=BD

∠BDC=∠BCD (∠s opposite to equal sides)

∠BDC=y=∠BCD

∠BDC=64

∘

=∠BCD

Now, z+64

∘

+64

∘

=180

∘

(Sum of ∠s of a Δ)

⇒Z+128

∘

=180

∘

⇒Z=180

∘

−128

∘

=52

∘

Hence,x=32

∘

,y=64

∘

,z=52

∘

solution