Question

Level - 1
1. An object is at a speed of 10 m/s accelerated and covers 300 m with a final velocity of
20 m/s, then the acceleration is
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Answer 1

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Here, u = 10m/s

v = 20 m/s

s = 300 m

Using third equation of motion,

v^2 = u^2 + 2as

=> (20)^2 = (10)^2 + 2a(300)

=> 400 = 100 + 600a

=> 600a = 300

=> a = 1/2

=> a = 0.5

Thus, acceleration is 0.5 m/s^2.

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Answer 2

Given:-

• Initial velocity (u) = 10 m/s
• Distance travelled (s) = 300 m
• Final velocity (v) = 20 m/s

To Find: Acceleration.

We know,

2as = v² - u²

where,

• a = Acceleration,
• s = Distance travelled,
• v, u = Final and initial velocity respectively.

So,

Let the acceleration be = a

∴ 2a (300 m) = (20 m/s)² - (10 m/s)²

→ 2a (300 m) = 400 m²/s² - 100 m²/s²

→ 2a (300 m) = 300 m²/s²

→ 2a = (300 m²/s²)/(300 m)

→ 2a = 1 m/s²

→ a = ½ m/s²

∴ The acceleration was 0.5 m/s².