Question

LEVEL 1
1. If a+b+c=0, then write the value of a³+b³+c³​

Answer 1

thank u dear ... follow me ...

Answer 2

Step-by-step explanation:

$a+b+c=0\\a^{3}+b^{3}+c^{3}-3abc=(a+b+c)(a^{2}+b^{2}+c^{2}-ab-bc-ac)\\=>a^{3}+b^{3}+c^{3}-3abc=0(a^{2}+b^{2}+c^{2}-ab-bc-ac)=0\\=>a^{3}+b^{3}+c^{3}=3abc$

Hope you have understood the answer.

Thank you.

Plzzz mark my answer as brainliest.