Question

LEVEL-2
3. If Zeba were younger by 5 years than what she really is, then the square of her age (in
years) would have been 11 more than 5 times her actual age. What is her age now?
[NCERT EXEMPLAR]​

Answer 1

Answer:

let age of zeba now be x

ATQ

(x-5)^2 = 5x + 11.

x2 + 25 -10x = 5x + 11

x2 - 15x + 14 = 0

x2 - 14x - x + 14 = 0

x(x-14) -1(x-14) = 0

so, x = 14 , 1.

but if x = 1 then her age 5 yrs ago will be -4 which is not possible so her present age = 14.

Step-by-step explanation:

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