Question

LEVEL-2
7. PQR is a triangle in which PQ = PR and S is any point on the side PQ. Through S, a
line is drawn parallel to QR and intersecting PR at T. Prove that PS = PT.
8. In a AARC it
$? \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?}$
​

Answer 1

Answer:

PT=PS

Step-by-step explanation:

In ΔPQR, we have

PQ=PR⇒∠R=∠Q

Now, ST∥QR.

⇒∠PST=∠PQR and ∠PTS=∠PRQ     [∵ Corresponding angles are equal]

⇒∠PST=∠Q and ∠PTS=∠R

⇒∠PST=∠PTS

⇒PT=PS